Optimal. Leaf size=443 \[ \frac{2 \left (8 a^2 C+3 b^2 (11 A+9 C)\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{231 b^3 d}-\frac{4 a \left (8 a^2 C+33 A b^2+34 b^2 C\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{1155 b^3 d}-\frac{2 \left (6 a^2 b^2 (11 A+8 C)+16 a^4 C-25 b^4 (11 A+9 C)\right ) \sin (c+d x) \sqrt{a+b \cos (c+d x)}}{1155 b^3 d}+\frac{2 \left (a^2-b^2\right ) \left (6 a^2 b^2 (11 A+8 C)+16 a^4 C-25 b^4 (11 A+9 C)\right ) \sqrt{\frac{a+b \cos (c+d x)}{a+b}} F\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )}{1155 b^4 d \sqrt{a+b \cos (c+d x)}}-\frac{4 a \left (3 a^2 b^2 (11 A+6 C)+8 a^4 C-b^4 (451 A+348 C)\right ) \sqrt{a+b \cos (c+d x)} E\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )}{1155 b^4 d \sqrt{\frac{a+b \cos (c+d x)}{a+b}}}-\frac{4 a C \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{33 b^2 d}+\frac{2 C \sin (c+d x) \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2}}{11 b d} \]
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Rubi [A] time = 1.06326, antiderivative size = 443, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 9, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.257, Rules used = {3050, 3049, 3023, 2753, 2752, 2663, 2661, 2655, 2653} \[ \frac{2 \left (8 a^2 C+3 b^2 (11 A+9 C)\right ) \sin (c+d x) (a+b \cos (c+d x))^{5/2}}{231 b^3 d}-\frac{4 a \left (8 a^2 C+33 A b^2+34 b^2 C\right ) \sin (c+d x) (a+b \cos (c+d x))^{3/2}}{1155 b^3 d}-\frac{2 \left (6 a^2 b^2 (11 A+8 C)+16 a^4 C-25 b^4 (11 A+9 C)\right ) \sin (c+d x) \sqrt{a+b \cos (c+d x)}}{1155 b^3 d}+\frac{2 \left (a^2-b^2\right ) \left (6 a^2 b^2 (11 A+8 C)+16 a^4 C-25 b^4 (11 A+9 C)\right ) \sqrt{\frac{a+b \cos (c+d x)}{a+b}} F\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )}{1155 b^4 d \sqrt{a+b \cos (c+d x)}}-\frac{4 a \left (3 a^2 b^2 (11 A+6 C)+8 a^4 C-b^4 (451 A+348 C)\right ) \sqrt{a+b \cos (c+d x)} E\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )}{1155 b^4 d \sqrt{\frac{a+b \cos (c+d x)}{a+b}}}-\frac{4 a C \sin (c+d x) \cos (c+d x) (a+b \cos (c+d x))^{5/2}}{33 b^2 d}+\frac{2 C \sin (c+d x) \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2}}{11 b d} \]
Antiderivative was successfully verified.
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Rule 3050
Rule 3049
Rule 3023
Rule 2753
Rule 2752
Rule 2663
Rule 2661
Rule 2655
Rule 2653
Rubi steps
\begin{align*} \int \cos ^2(c+d x) (a+b \cos (c+d x))^{3/2} \left (A+C \cos ^2(c+d x)\right ) \, dx &=\frac{2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{11 b d}+\frac{2 \int \cos (c+d x) (a+b \cos (c+d x))^{3/2} \left (2 a C+\frac{1}{2} b (11 A+9 C) \cos (c+d x)-3 a C \cos ^2(c+d x)\right ) \, dx}{11 b}\\ &=-\frac{4 a C \cos (c+d x) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{33 b^2 d}+\frac{2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{11 b d}+\frac{4 \int (a+b \cos (c+d x))^{3/2} \left (-3 a^2 C-\frac{3}{2} a b C \cos (c+d x)+\frac{3}{4} \left (8 a^2 C+3 b^2 (11 A+9 C)\right ) \cos ^2(c+d x)\right ) \, dx}{99 b^2}\\ &=\frac{2 \left (8 a^2 C+3 b^2 (11 A+9 C)\right ) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{231 b^3 d}-\frac{4 a C \cos (c+d x) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{33 b^2 d}+\frac{2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{11 b d}+\frac{8 \int (a+b \cos (c+d x))^{3/2} \left (\frac{9}{8} b \left (55 A b^2+4 a^2 C+45 b^2 C\right )-\frac{3}{4} a \left (33 A b^2+8 a^2 C+34 b^2 C\right ) \cos (c+d x)\right ) \, dx}{693 b^3}\\ &=-\frac{4 a \left (33 A b^2+8 a^2 C+34 b^2 C\right ) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{1155 b^3 d}+\frac{2 \left (8 a^2 C+3 b^2 (11 A+9 C)\right ) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{231 b^3 d}-\frac{4 a C \cos (c+d x) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{33 b^2 d}+\frac{2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{11 b d}+\frac{16 \int \sqrt{a+b \cos (c+d x)} \left (\frac{9}{16} a b \left (209 A b^2+4 a^2 C+157 b^2 C\right )-\frac{9}{16} \left (16 a^4 C+6 a^2 b^2 (11 A+8 C)-25 b^4 (11 A+9 C)\right ) \cos (c+d x)\right ) \, dx}{3465 b^3}\\ &=-\frac{2 \left (16 a^4 C+6 a^2 b^2 (11 A+8 C)-25 b^4 (11 A+9 C)\right ) \sqrt{a+b \cos (c+d x)} \sin (c+d x)}{1155 b^3 d}-\frac{4 a \left (33 A b^2+8 a^2 C+34 b^2 C\right ) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{1155 b^3 d}+\frac{2 \left (8 a^2 C+3 b^2 (11 A+9 C)\right ) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{231 b^3 d}-\frac{4 a C \cos (c+d x) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{33 b^2 d}+\frac{2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{11 b d}+\frac{32 \int \frac{-\frac{9}{32} b \left (4 a^4 C-25 b^4 (11 A+9 C)-3 a^2 b^2 (187 A+141 C)\right )-\frac{9}{16} a \left (8 a^4 C+3 a^2 b^2 (11 A+6 C)-b^4 (451 A+348 C)\right ) \cos (c+d x)}{\sqrt{a+b \cos (c+d x)}} \, dx}{10395 b^3}\\ &=-\frac{2 \left (16 a^4 C+6 a^2 b^2 (11 A+8 C)-25 b^4 (11 A+9 C)\right ) \sqrt{a+b \cos (c+d x)} \sin (c+d x)}{1155 b^3 d}-\frac{4 a \left (33 A b^2+8 a^2 C+34 b^2 C\right ) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{1155 b^3 d}+\frac{2 \left (8 a^2 C+3 b^2 (11 A+9 C)\right ) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{231 b^3 d}-\frac{4 a C \cos (c+d x) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{33 b^2 d}+\frac{2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{11 b d}+\frac{\left (\left (a^2-b^2\right ) \left (16 a^4 C+6 a^2 b^2 (11 A+8 C)-25 b^4 (11 A+9 C)\right )\right ) \int \frac{1}{\sqrt{a+b \cos (c+d x)}} \, dx}{1155 b^4}-\frac{\left (2 a \left (8 a^4 C+3 a^2 b^2 (11 A+6 C)-b^4 (451 A+348 C)\right )\right ) \int \sqrt{a+b \cos (c+d x)} \, dx}{1155 b^4}\\ &=-\frac{2 \left (16 a^4 C+6 a^2 b^2 (11 A+8 C)-25 b^4 (11 A+9 C)\right ) \sqrt{a+b \cos (c+d x)} \sin (c+d x)}{1155 b^3 d}-\frac{4 a \left (33 A b^2+8 a^2 C+34 b^2 C\right ) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{1155 b^3 d}+\frac{2 \left (8 a^2 C+3 b^2 (11 A+9 C)\right ) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{231 b^3 d}-\frac{4 a C \cos (c+d x) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{33 b^2 d}+\frac{2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{11 b d}-\frac{\left (2 a \left (8 a^4 C+3 a^2 b^2 (11 A+6 C)-b^4 (451 A+348 C)\right ) \sqrt{a+b \cos (c+d x)}\right ) \int \sqrt{\frac{a}{a+b}+\frac{b \cos (c+d x)}{a+b}} \, dx}{1155 b^4 \sqrt{\frac{a+b \cos (c+d x)}{a+b}}}+\frac{\left (\left (a^2-b^2\right ) \left (16 a^4 C+6 a^2 b^2 (11 A+8 C)-25 b^4 (11 A+9 C)\right ) \sqrt{\frac{a+b \cos (c+d x)}{a+b}}\right ) \int \frac{1}{\sqrt{\frac{a}{a+b}+\frac{b \cos (c+d x)}{a+b}}} \, dx}{1155 b^4 \sqrt{a+b \cos (c+d x)}}\\ &=-\frac{4 a \left (8 a^4 C+3 a^2 b^2 (11 A+6 C)-b^4 (451 A+348 C)\right ) \sqrt{a+b \cos (c+d x)} E\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )}{1155 b^4 d \sqrt{\frac{a+b \cos (c+d x)}{a+b}}}+\frac{2 \left (a^2-b^2\right ) \left (16 a^4 C+6 a^2 b^2 (11 A+8 C)-25 b^4 (11 A+9 C)\right ) \sqrt{\frac{a+b \cos (c+d x)}{a+b}} F\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )}{1155 b^4 d \sqrt{a+b \cos (c+d x)}}-\frac{2 \left (16 a^4 C+6 a^2 b^2 (11 A+8 C)-25 b^4 (11 A+9 C)\right ) \sqrt{a+b \cos (c+d x)} \sin (c+d x)}{1155 b^3 d}-\frac{4 a \left (33 A b^2+8 a^2 C+34 b^2 C\right ) (a+b \cos (c+d x))^{3/2} \sin (c+d x)}{1155 b^3 d}+\frac{2 \left (8 a^2 C+3 b^2 (11 A+9 C)\right ) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{231 b^3 d}-\frac{4 a C \cos (c+d x) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{33 b^2 d}+\frac{2 C \cos ^2(c+d x) (a+b \cos (c+d x))^{5/2} \sin (c+d x)}{11 b d}\\ \end{align*}
Mathematica [A] time = 1.74965, size = 331, normalized size = 0.75 \[ \frac{b (a+b \cos (c+d x)) \left (2 \left (6 a^2 b^2 (44 A+27 C)+64 a^4 C+5 b^4 (506 A+435 C)\right ) \sin (c+d x)+b \left (16 a \left (-3 a^2 C+132 A b^2+136 b^2 C\right ) \sin (2 (c+d x))+5 b \left (\left (4 a^2 C+132 A b^2+171 b^2 C\right ) \sin (3 (c+d x))+7 b C (8 a \sin (4 (c+d x))+3 b \sin (5 (c+d x)))\right )\right )\right )+16 \sqrt{\frac{a+b \cos (c+d x)}{a+b}} \left (b \left (3 a^2 b^3 (187 A+141 C)-4 a^4 b C+25 b^5 (11 A+9 C)\right ) F\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )-2 a \left (3 a^2 b^2 (11 A+6 C)+8 a^4 C-b^4 (451 A+348 C)\right ) \left ((a+b) E\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )-a F\left (\frac{1}{2} (c+d x)|\frac{2 b}{a+b}\right )\right )\right )}{9240 b^4 d \sqrt{a+b \cos (c+d x)}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.428, size = 1791, normalized size = 4. \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (C \cos \left (d x + c\right )^{2} + A\right )}{\left (b \cos \left (d x + c\right ) + a\right )}^{\frac{3}{2}} \cos \left (d x + c\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (C b \cos \left (d x + c\right )^{5} + C a \cos \left (d x + c\right )^{4} + A b \cos \left (d x + c\right )^{3} + A a \cos \left (d x + c\right )^{2}\right )} \sqrt{b \cos \left (d x + c\right ) + a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (C \cos \left (d x + c\right )^{2} + A\right )}{\left (b \cos \left (d x + c\right ) + a\right )}^{\frac{3}{2}} \cos \left (d x + c\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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